Utility to compile possibly incomplete Python source code.
- compile_command(source, filename='<input>', symbol='single')
- Compile a command and determine whether it is incomplete.
source -- the source string; may contain \n characters
filename -- optional filename from which source was read; default "<input>"
symbol -- optional grammar start symbol; "single" (default) or "eval"
Return value / exceptions raised:
- Return a code object if the command is complete and valid
- Return None if the command is incomplete
- Raise SyntaxError or OverflowError if the command is a syntax error
(OverflowError if the error is in a numeric constant)
First, check if the source consists entirely of blank lines and
comments; if so, replace it with 'pass', because the built-in
parser doesn't always do the right thing for these.
Compile three times: as is, with \n, and with \n\n appended. If
it compiles as is, it's complete. If it compiles with one \n
appended, we expect more. If it doesn't compile either way, we
compare the error we get when compiling with \n or \n\n appended.
If the errors are the same, the code is broken. But if the errors
are different, we expect more. Not intuitive; not even guaranteed
to hold in future releases; but this matches the compiler's
behavior from Python 1.4 through 1.5.2, at least.
It is possible (but not likely) that the parser stops parsing
with a successful outcome before reaching the end of the source;
in this case, trailing symbols may be ignored instead of causing an
error. For example, a backslash followed by two newlines may be
followed by arbitrary garbage. This will be fixed once the API
for the parser is better.
||__all__ = ['compile_command']|
__file__ = '/usr/lib/python2.1/codeop.pyc'
__name__ = 'codeop'